Birthday Problem

How likely is it that two or more people in your class have the same birthday?

A formula to accompany the Birthday Problem
Let's look at the probabilities a step at a time.

For one person, there are 365 distinct birthdays.
For two people, there are 364 different ways that the second could have a birthday without matching the first.
If there is no match after two people, the third person has 363 different birthdays that do not match the other two. So, the probability of a match is 1 - (365)(364)(363)/(365)(365)(365).
This leads to the following formula for calculating the probability of a match with N birthdays is 1 - (365)(364)(363)...(365 - N + 1)/(365)^N.
Running this through a computer gives the chart below. Notice that a probability of over .5 is obtained after 23 dates!


Notice that the probability is above .9
before the sample size reaches even 45.

Why do I find this so interesting? I feel like I should take note of my interest in probability as I explore careers.